Question:

99% of a first order reaction was completed in 32 minutes. When will 99.9% of the reaction complete?

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For first-order reactions: \[ t_{90%} : t_{99%} : t_{99.9%} = 1 : 2 : 3 \] Use this direct ratio method to solve questions quickly.
Updated On: May 19, 2026
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The Correct Option is A

Solution and Explanation

Concept: For first-order reactions: \[ t = \frac{2.303}{k}\log\frac{a}{a-x} \] Special results: \[ t_{90%} = \frac{2.303}{k} \] \[ t_{99%} = \frac{4.606}{k} \] \[ t_{99.9%} = \frac{6.909}{k} \] Hence: \[ t_{99.9%} = \frac{3}{2}t_{99%} \]

Step 1: Write given information
Given: \[ t_{99%} = 32 \text{ minutes} \] We use relation: \[ \frac{t_{99.9%}}{t_{99%}} = \frac{3}{2} \]

Step 2: Calculate \(t_{99.9%}\)
\[ t_{99.9%} = \frac{3}{2}\times 32 \] \[ = 48 \text{ minutes} \] Final Answer: \[ \boxed{48 \text{ minutes}} \]
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