The correct answer is 180.
To prepare 500 mL of 0.1 M NaOH solution, we need to calculate the volume of the stock solution required.
First, let's calculate the number of moles of NaOH in 500 mL of 0.1 M solution:
Number of moles of NaOH = Molarity × Volume (in L) Number of moles of NaOH = 0.1 × 0.5 Number of moles of NaOH = 0.05
Next, let's calculate the number of moles of NaOH in the stock solution:
Number of moles of NaOH in stock solution = (mass of NaOH / molar mass of NaOH) = (5 g / 40 g/mol) = 0.125 mol
Now, we can use the following formula to calculate the volume of the stock solution required:
Volume of stock solution = (Number of moles required / Number of moles in stock solution) × Volume of stock solution
Plugging in the values, we get:
Volume of stock solution = (0.05 / 0.125) × 0.45 L Volume of stock solution = 0.18 L = 180 mL
Therefore, 180 mL of the NaOH stock solution is required to prepare 500 mL of 0.1 M NaOH solution.
The correct answer is 180
\(M=\frac{5}{40} \times \frac{1000}{450}\)
\(M_1V_1=M_2V_2\)
\((\frac{5}{40} \times \frac{1000}{450})\times V_1=0.1 \times 500\)
\(V_1=180\)
\(\therefore\) volume required is 180
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| Sample | Van't Haff Factor |
|---|---|
| Sample - 1 (0.1 M) | \(i_1\) |
| Sample - 2 (0.01 M) | \(i_2\) |
| Sample - 3 (0.001 M) | \(i_2\) |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: