Question:
32P and 35S were used because:
A. Both P and S are absent in RNA
B. P and S both are present in DNA and protein
C. P is present in DNA and S is present in protein only
D. Selective labeling of DNA and protein can be done with 32P and 35S
E. Both are easily available in gaseous form
Choose the correct answer from the options given below:
32P and 35S were used because:
A. Both P and S are absent in RNA
B. P and S both are present in DNA and protein
C. P is present in DNA and S is present in protein only
D. Selective labeling of DNA and protein can be done with 32P and 35S
E. Both are easily available in gaseous form
Choose the correct answer from the options given below:
A. Both P and S are absent in RNA
B. P and S both are present in DNA and protein
C. P is present in DNA and S is present in protein only
D. Selective labeling of DNA and protein can be done with 32P and 35S
E. Both are easily available in gaseous form
Choose the correct answer from the options given below:
Show Hint
Hershey-Chase experiment:
- 32P: Labels DNA (phosphorus).
- 35S: Labels protein (sulfur).
- Proved DNA is the genetic material.
- 32P: Labels DNA (phosphorus).
- 35S: Labels protein (sulfur).
- Proved DNA is the genetic material.
Updated On: Aug 27, 2026
- A and E only
- C and D only
- B and D only
- C and E only
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understanding the Question:
This question tests knowledge of the Hershey-Chase experiment.
Step 2: Detailed Explanation:
In the Hershey-Chase experiment, 32P and 35S were used to label DNA and proteins.
C. P is present in DNA and S is present in protein only: Correct.
Phosphorus (P) is present in DNA, while sulfur (S) is present in proteins (cysteine and methionine).
D. Selective labeling of DNA and protein can be done with 32P and 35S: Correct.
32P labels DNA, and 35S labels proteins, allowing selective tracking.
Other options:
- Both P and S are absent in RNA (A): Incorrect (P is present in RNA).
- P and S both are present in DNA and protein (B): Incorrect (S is not present in DNA).
- Both are easily available in gaseous form (E): Incorrect.
Thus, C and D are correct.
Step 3: Final Answer:
Thus, the correct answer is C and D only, which corresponds to option (B).
[0.5cm]
This question tests knowledge of the Hershey-Chase experiment.
Step 2: Detailed Explanation:
In the Hershey-Chase experiment, 32P and 35S were used to label DNA and proteins.
C. P is present in DNA and S is present in protein only: Correct.
Phosphorus (P) is present in DNA, while sulfur (S) is present in proteins (cysteine and methionine).
D. Selective labeling of DNA and protein can be done with 32P and 35S: Correct.
32P labels DNA, and 35S labels proteins, allowing selective tracking.
Other options:
- Both P and S are absent in RNA (A): Incorrect (P is present in RNA).
- P and S both are present in DNA and protein (B): Incorrect (S is not present in DNA).
- Both are easily available in gaseous form (E): Incorrect.
Thus, C and D are correct.
Step 3: Final Answer:
Thus, the correct answer is C and D only, which corresponds to option (B).
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