Question:
10 people went to a restaurant to have a meal as a group. Of these, 9 had already contributed Rs 400 each, while the 10th person had to give the entire additional amount required to honour the restaurant's bill. How much did this person pay if he had to pay Rs 900 more than the group's average?
10 people went to a restaurant to have a meal as a group. Of these, 9 had already contributed Rs 400 each, while the 10th person had to give the entire additional amount required to honour the restaurant's bill. How much did this person pay if he had to pay Rs 900 more than the group's average?
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The 10th person pays the Average + the excess, which is the total payment.
Updated On: Jun 12, 2026
- Rs 1360
- Rs 1350
- Rs 1400
- Rs 1300
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Algebraic representation of Average (A).
Step 2: Detailed Explanation:
1. Sum = \( 9 \times 400 + (\text{Avg} + 900) = 10 \times \text{Avg} \).
2. \( 3600 + 900 = 10 \times \text{Avg} - \text{Avg} = 9 \times \text{Avg} \).
3. \( 4500 = 9 \times \text{Avg} \implies \text{Avg} = 500 \).
4. 10th person = \( 500 + 900 = 1400 \).
Step 3: Final Answer:
The person paid Rs 1400.
Algebraic representation of Average (A).
Step 2: Detailed Explanation:
1. Sum = \( 9 \times 400 + (\text{Avg} + 900) = 10 \times \text{Avg} \).
2. \( 3600 + 900 = 10 \times \text{Avg} - \text{Avg} = 9 \times \text{Avg} \).
3. \( 4500 = 9 \times \text{Avg} \implies \text{Avg} = 500 \).
4. 10th person = \( 500 + 900 = 1400 \).
Step 3: Final Answer:
The person paid Rs 1400.
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