1- methyl ethylene oxide when treated with an excess of HBr produces :
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The Correct Option is A
Solution and Explanation
HBr protonates the oxygen and Br- opens the ring to give a bromohydrin (CH3CH(OH)CH2Br or CH3CHBrCH2OH).
With excess HBr the remaining alcoholic -OH is also replaced by Br (R-OH + HBr \( o\) R-Br + H2O).
The final product is 1,2-dibromopropane, CH3CHBrCH2Br, the structure with Br on adjacent carbons and one CH3 shown in the first option.
Answer: (A) 1,2-dibromopropane
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