\(ΔT_f =\frac { k_f \times W_1 \times1000 }{W_2 \times M_1}\)
Where,
W1 = Weight of the solute
W2 = Weight of solvent
M1 = Molar mass of solute
kf = Freezing point depression constant
\(ΔT_f = \frac {5.12 \times 1\times 1000}{51.2 \times 250}\)
\(ΔT_f = 0.4\ K\)
So, the correct option is (A): 0.4 K
1 M and 2.5 litre NaOH solution mixed with another 0.5 M and 3 litre NaOH solution. Then find out molarity of resultant solution
A solution contains non volatile solute of molecular mass M2. Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure
Solutions are homogeneous mixtures of two or more substances, where the solute is uniformly dispersed in the solvent. Solutions can be classified into several types based on their composition and properties.
Understanding the different types of solutions is important for understanding their properties, behavior, and applications in various fields, such as chemistry, biology, and engineering.