If \( V_1 \) is the velocity of a body projected from point A and \( V_2 \) is the velocity of a body projected from point B, which is vertically below the highest point C, and if both the bodies collide, then:
For the circuit shown in the figure, the current through the inductor is \( 0.9A \) while the current through the condenser is \( 0.4A \). Then:
The P-V diagram of a diatomic ideal gas system undergoing a cyclic process is shown in the figure. The work done during the adiabatic process \( CD \) is (Use \( \gamma = 1.4 \)):
An object moves with speed \( v_1 \), \( v_2 \), and \( v_3 \) along a line segment \( AB \), \( BC \), and \( CD \) respectively as shown in the figure. Where \( AB = BC \) and \( AD = 3 AB \), then the average speed of the object will be:
A proton (\( p \)) and an electron (\( e \)) will have the same de-Broglie wavelength when the ratio of their momenta is (Assume \( m_p = 1849 m_e \)):
The energy levels of an atom are shown in the figure. Which one of these transitions will result in the emission of a photon of wavelength 124.1 nm? Given \( h = 6.62 \times 10^{-34} \) Js.