Let the eccentricity of an ellipse \(\frac {x^2}{a^2}+\frac {y^2}{b^2}=1\), \(a>b\), be \(\frac 14\). If this ellipse passes through the point \((−4\sqrt {\frac 25},3)\), then \(a^2 + b^2\) is equal to :
The general solution of the differential equation \(\left(x-y^2\right) d x+y\left(5 x+y^2\right) d y=0\) is :