Let
\(a→=α\^{i}+3\^{j}−\^{k}, \overrightarrow{b}=3\^{i}−β\^{j}+4\^{k} and \overrightarrow{c}=\^{i}+2\^{j}−2\^{k }\)
where α,β∈R, be three vectors. If the projection of
\(\overrightarrow{a} on \overrightarrow{c} is \frac{10}{3} and \overrightarrow{b}×\overrightarrow{c}=−6\^{i}+10\^{j}+7\^{k}, \)
then the value of α+β is equal to
The area enclosed by y2 = 8x and y = √2x that lies outside the triangle formed by \(y=√2x,x=1,y=2√2\), is equal to
If the system of linear equations
2x + y – z = 7
x – 3y + 2z = 1
x + 4y + δz = k, where δ, k ∈ R
has infinitely many solutions, then δ + k is equal to:
Letƒ : R → Rbe defined as f(x) = x -1 andg : R - { 1, -1 } → Rbe defined asg(x) = \(\frac{x²}{x² - 1}\)Then the function fog is :
\(\lim_{{x \to 0}} \limits\) \(\frac{cos(sin x) - cos x }{x^4}\) is equal to :
The normal to the hyperbola\(\frac{x²}{a²} - \frac{y²}{9} = 1\)at the point (8, 3√3) on it passes through the point:
If the lines\(\stackrel{→}{r}= ( \hat{i} - \hat{j} + \hat{k} ) + λ (\hat{3j} - \hat{k} )= ( \hat{i} - \hat{j} + \hat{k} ) + λ (\hat{3j} - \hat{k} )\)and\(\stackrel{→}{r} = ( \alpha \hat{i} - \hat{j} ) + μ( \hat{2j} - \hat{3k} )\)are co-planer , then the distance of the plane containing these two lines from the point \(( α , 0 , 0 )\) is :
Let \(\stackrel{→}{a} = \hat{i} + \hat{j} + \hat{2k}, \stackrel{→}{b} = \hat{2i} - \hat{3j} + \hat{k}\)and \(\stackrel{→}{c}= \hat{i} - \hat{j} + \hat{k}\)be three given vectors.Let \(\stackrel{→}{v}\) be a vector in the plane of \(\stackrel{→}{a}\) and \(\stackrel{→}{b}\) whose projection on \(\stackrel{→}{c}\) is \(\frac{2}{\sqrt3}\).If \(\stackrel{→}{v}.\hat{j}\) = 7 , then \(\stackrel{→}{v}.(\hat{i}+\hat{k})\) is equal to :