If the de Broglie wavelength of an electron is equal to the \(10^{-3}\) times the wavelength of a photon of frequency \(6 \times 10^{14}\) Hz, then the speed of electron is equal to : (Speed of light = \(3 \times 10^{8}\) m/s, Planck's constant = \(6.63 \times 10^{-34}\) J.s, Mass of electron = \(9.1 \times 10^{-31}\) kg)