The shortest distance between the lines \(x+1=2 y=-12 z\) and \(x=y+2=6 z-6\) is
Consider the lines $L_1$ and $L_2$ given by $L_1: \frac{x-1}{2}=\frac{y-3}{1}=\frac{z-2}{2} $ $L_2: \frac{x-2}{1}=\frac{y-2}{2}=\frac{z-3}{3} $ A line $L_3$ having direction ratios $1,-1,-2$, intersects $L_1$ and $L_2$ at the points $P$ and $Q$ respectively Then the length of line segment $P Q$ is
The mean and variance of the marks obtained by the students in a test are 10 and 4 respectively Later, the marks of one of the students is increased from 8 to 12 If the new mean of the marks is $10.2$, then their new variance is equal to :