An excited He\(^+\) ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength \(\lambda\), energy
\(E=\frac{1240\,\mathrm{eV}}{\lambda\,(\text{in nm})}\)
) :