Let p, q and r be three mutually perpendicular vectors of the same magnitude. If a vector x satisfies equation p x {(x - q) x p} + q x {(x - r) x r} + r x {(x - p) x r} = 0, then x is given by
Let $y=y(x)$ be the solution of the differential equation $\left(x^2-3 y^2\right) d x+3 x y d y=0, y(1)=1$.Then $6 y^2( e )$ is equal to