In the circuit, the logical value of A = 1 or B = 1 when potential at A or B is 5 V and the logical value of A = 0 or B = 0 when potential at A or B is 0 V. The truth table of the given circuit will be:
Letƒ : R → Rbe defined as f(x) = x -1 andg : R - { 1, -1 } → Rbe defined asg(x) = \(\frac{x²}{x² - 1}\)Then the function fog is :
If A =\(\sum_{n=1}^{\infty}\)\(\frac{1}{( 3 + (-1)^n)^n}\) and B = \(\sum_{n=1}^{\infty}\) \(\frac{(-1)^n}{( 3 + (-1)^n)^n}\) , then A/B is equal to :
\(\lim_{{x \to 0}} \limits\) \(\frac{cos(sin x) - cos x }{x^4}\) is equal to :
If \(∫\frac{1}{x}\) \(√{\frac{1-x}{1+x}}\) dx = \(g(x) + c,g(1) = 0\) , then g \((\frac{1}{2})\) is equal to
If y = y(x) is the solution of the differential equation\(x\) \(\frac{dy}{dx}\) \(+ 2y =\) \(xe^x , y(1) = 0\)then the local maximum value of the function\(z(x) = x²y(x) - e^x , x ∈ R\)is