The circuit shown below uses an ideal OpAmp. Output \( V_o \) in volt is \(\underline{\hspace{2cm}}\) (rounded off to one decimal place).
All the transistors used in the circuit are matched and have a current gain \( \beta = 20 \). Neglecting the Early effect, the current \( I_{O4} \) in milliamperes is \(\underline{\hspace{2cm}}\).
