List of top General Aptitude Questions asked in CAT

There were 'x' pigeons and 'y' mynahs in a cage. One fine morning, 'p' birds escaped to freedom. The bird-keeper, knowing only that p = 7, was able to figure out without looking into the cage that at least one pigeon had escaped. Which of the following does not represent a possible (x,y) pair?
The .............., those cellular bodies which contain the .............. particles, the genes, provide us with basic facts of genetic transmission.
The insurance claim was .............. by the relevant documents.
I should not have .............. to talk in such a .............. strain especially when I had not studied the man to whom I was talking.
A, B and C individually can finish a work in 6, 8 and 15 hours respectively. They started the work together and after completing the work got Rs. 94.60 in all. When they divide the money among themselves, A, B and C will respectively get (in Rs.):
A square is drawn by joining the midpoints of the sides of a given square. A third square is drawn inside the second square in the same way and this process is continued indefinitely. If a side of the first square is 8 cm, the sum of the areas of all the squares thus formed (in sq.cm) is:
The value of $\frac{(1 - d^3)}{(1 - d)}$ is:
Consider the following steps:
1. Put $x = 1$, $y = 2$
2. Replace $x$ by $xy$
3. Replace $y$ by $y + 1$
4. If $y = 5$ then go to step 6 otherwise go to step 5
5. Go to step 2
6. Stop
Then the final value of $x$ equals:
116 people participated in a singles tennis tournament of knockout format. The players are paired up in the first round, winners of the first round are paired in the second round, and so on till the final is played between two players. If after any round, the number of players is odd, one player is given a bye (he skips that round and plays the next round with the winners). Find the total number of matches played in the tournament.
The remainder when $26^{60}$ is divided by 5 equals:
What is the sum of the following series:
$\frac{1}{1 \times 2} + \frac{1}{2 \times 3} + \frac{1}{3 \times 4} + + \frac{1}{100 \times 101}$