Question

(X) \(\text{NH}_3\), \(\Delta\) \(\longrightarrow\) (A)
(i) KOH + Br$_2$
(ii) CHCl$_3$, NaOH
X will be:

• A. 1
• B. 2
• C. 3
• D. 4

Hint:

The Hofmann bromamide reaction leads to the formation of primary amines, and reactions with CHCl$_3$ and NaOH can lead to the formation of carboxylic acids, often by malonic ester synthesis.

Answer 1

The Correct Option is C

Step 1: Understanding the reaction.
The reaction involves the conversion of ammonia to a compound (A) using KOH and Br$_2$. This is indicative of the Hofmann bromamide reaction, where an amide (such as (A)) is treated with bromine and a strong base to yield an amine.
Step 2: Analyzing the second reaction.
The second step involves treating the product (A) with CHCl$_3$ and NaOH, which is indicative of the malonic ester synthesis or similar reactions to form a carboxylic acid. Here, the structure of (A) is likely to be an acetamide (CH$_3$CONH$_2$).
Step 3: Conclusion.
After the two reactions, the product X will be CH$_2$COOH, as it follows the structure of the carboxylic acid produced from the Hofmann and malonic ester-like reactions.