Question:
‘X’ is the nitrogen containing compound which is added to freshly prepared FeSO\(_4\) and dilute H\(_2\)SO\(_4\) to form a brown ring complex ‘Y’.
Identify X and Y.
‘X’ is the nitrogen containing compound which is added to freshly prepared FeSO\(_4\) and dilute H\(_2\)SO\(_4\) to form a brown ring complex ‘Y’.
Identify X and Y.
Identify X and Y.
Show Hint
The formation of a brown ring complex is a classical test for the presence of nitrate ions, where NO binds to Fe\(^{2+}\) in the presence of dilute H\(_2\)SO\(_4\).
Updated On: Apr 7, 2026
- NO; [Fe(NO)]SO\(_4\)
- N\(_2\)O; [Fe(N\(_2\)O)]SO\(_4\)
- NO\(_2\); [Fe(NO\(_2\))]SO\(_4\)
- N\(_2\)O\(_4\); [Fe(N\(_2\)O\(_4\))]SO\(_4\)
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Understanding the Brown Ring Complex.
The brown ring complex is a characteristic complex formed when nitric oxide (NO) is added to freshly prepared FeSO\(_4\) (iron(II) sulfate) in the presence of dilute H\(_2\)SO\(_4\). The reaction involves the formation of a complex where NO binds to Fe\(^{2+}\) to form [Fe(NO)]\(^{2+}\) with a brown ring. The reaction is: \[ Fe^{2+} + NO \rightarrow [Fe(NO)]^{2+} \] This results in a brown complex, known as the brown ring complex.
Step 2: Analyzing the Options.
- (A) NO; [Fe(NO)]SO\(_4\): Correct. This is the known reaction for the brown ring complex. - (B) N\(_2\)O; [Fe(N\(_2\)O)]SO\(_4\): Incorrect. Nitrous oxide (N\(_2\)O) does not form a brown ring complex with iron(II). - (C) NO\(_2\); [Fe(NO\(_2\))]SO\(_4\): Incorrect. Nitrogen dioxide (NO\(_2\)) does not form a brown ring complex with iron. - (D) N\(_2\)O\(_4\); [Fe(N\(_2\)O\(_4\))]SO\(_4\): Incorrect. Dinitrogen tetroxide (N\(_2\)O\(_4\)) does not form a brown ring complex with iron.
Step 3: Conclusion.
The correct answer is option (A), where the nitrogen-containing compound is NO and the resulting complex is [Fe(NO)]SO\(_4\), which is the brown ring complex. Final Answer: Option (A) NO; [Fe(NO)]SO\(_4\).
The brown ring complex is a characteristic complex formed when nitric oxide (NO) is added to freshly prepared FeSO\(_4\) (iron(II) sulfate) in the presence of dilute H\(_2\)SO\(_4\). The reaction involves the formation of a complex where NO binds to Fe\(^{2+}\) to form [Fe(NO)]\(^{2+}\) with a brown ring. The reaction is: \[ Fe^{2+} + NO \rightarrow [Fe(NO)]^{2+} \] This results in a brown complex, known as the brown ring complex.
Step 2: Analyzing the Options.
- (A) NO; [Fe(NO)]SO\(_4\): Correct. This is the known reaction for the brown ring complex. - (B) N\(_2\)O; [Fe(N\(_2\)O)]SO\(_4\): Incorrect. Nitrous oxide (N\(_2\)O) does not form a brown ring complex with iron(II). - (C) NO\(_2\); [Fe(NO\(_2\))]SO\(_4\): Incorrect. Nitrogen dioxide (NO\(_2\)) does not form a brown ring complex with iron. - (D) N\(_2\)O\(_4\); [Fe(N\(_2\)O\(_4\))]SO\(_4\): Incorrect. Dinitrogen tetroxide (N\(_2\)O\(_4\)) does not form a brown ring complex with iron.
Step 3: Conclusion.
The correct answer is option (A), where the nitrogen-containing compound is NO and the resulting complex is [Fe(NO)]SO\(_4\), which is the brown ring complex. Final Answer: Option (A) NO; [Fe(NO)]SO\(_4\).
Was this answer helpful?
0
0
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
View More Questions
Top JEE Main Physical Chemistry Questions
- Consider the following equilibrium: \[ 2AB \rightleftharpoons A_2 + B_2 \] If equilibrium pressure is \(P\) and degree of dissociation is \(\alpha\), then \(K_p\) is
- Consider the following electrochemical cell \[ Zn | Zn^{2+}(aq) \, || \, Ag^{+}(aq) | Ag \] \[ [Zn^{2+}] = 1\,M \] The \(E_{cell\) was found to be \(1.6\,V\). The value of \(\log[Ag^+]\) is \[ E^\circ_{Zn^{2+}/Zn} = -0.76\,V , \qquad E^\circ_{Ag^+/Ag} = +0.80\,V \]
- For a first order reaction : \[ \text{A(g)} \rightarrow \text{B(g)} + \text{C(g)} \] If initial pressure is \( P_0 \) and total pressure at time \( t \) is \( P_t \), then the expression of rate constant \( K \) is:
- On heating \(2.76\,\text{g}\) of \( \text{Ag}_2\text{CO}_3 (s) \), some solid residue is left behind. Determine the mass of residue left.
- Determine mole fraction of water in an aqueous solution of urea having \(10\%\) w/w urea.
View More Questions
Top JEE Main Questions
- In a hydrogen like atom, when an electron jumps from the $M$ - shell to the $L$ - shell, the wavelength of emitted radiation is $\lambda$. If an electron jumps from $N$-shell to the $L$-shell, the wavelength of emitted radiation will be :
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
View More Questions