Step 1: Expand both quantities.
\[
(x-y)^2 = x^2 - 2xy + y^2, \quad (x+y)^2 = x^2 + 2xy + y^2
\]
Step 2: Compare.
The only difference is the middle term:
\[
(x+y)^2 - (x-y)^2 = 4xy
\]
Step 3: Analyze cases.
- If \(xy>0\) (both \(x\) and \(y\) same sign), then \((x+y)^2>(x-y)^2\).
- If \(xy<0\) (opposite signs), then \((x-y)^2>(x+y)^2\).
- If \(xy = 0\), it contradicts the condition that \(x,y \neq 0\).
So the relationship cannot be determined without knowing the signs of \(x\) and \(y\).
Final Answer:
\[
\boxed{\text{The answer cannot be determined from the information given.}}
\]