Question

Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: an = \(\frac{3}{6}\)

Answer 1

Substituting n = 1, 2, 3, 4, 5, we obtain

a1 = 2×1-\(\frac{3}{6} =\frac{-1}{6}\)

a2 = 2×2-\(\frac{3}{6} = \frac{1}{6}\)

a3 = 2×3-\(\frac{3}{6} = \frac{3}{6} = \frac{1}{2}\)

a4 = 2×4-\(\frac{3}{6} = \frac{5}{6}\)

a5 = 2×5-\(\frac{3}{6} = \frac{7}{6}\)

Therefore, the required terms are \(\frac{-1}{6}, \frac{1}{6},\frac{1}{2}, \frac{5}{6}, and \frac{7}{6}\)