When preparing Mohr’s salt, \(\text{H}_2\text{SO}_4\) is added for the following reasons:
Step 1: Understanding the role of \(\text{H}_2\text{SO}_4\)
Ferrous sulphate is prone to hydrolysis in aqueous solutions, especially when exposed to atmospheric oxygen. The hydrolysis leads to the formation of ferric hydroxide, which can contaminate the Mohr’s salt crystals.
Adding dilute sulphuric acid prevents the hydrolysis of ferrous sulphate by maintaining an acidic medium, which stabilizes the ferrous ions and prevents oxidation or decomposition.
Step 2: Reason for not choosing other options
Option (2): Ammonium sulphate does not hydrolyze under normal conditions, so preventing its hydrolysis is irrelevant.
Option (3): Although adding \(\text{H}_2\text{SO}_4\) makes the medium acidic, the main purpose is to prevent hydrolysis.
Option (4): The rate of formation of crystals is not directly influenced by \(\text{H}_2\text{SO}_4\) but rather by cooling and saturation.
Conclusion:
The correct reason for adding \(\text{H}_2\text{SO}_4\) is to prevent the hydrolysis of ferrous sulphate.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,