Question:

Which statements are True?
A. In Hoffmann bromamide degradation, 4 moles of NaOH and 2 moles of Br₂ are consumed per mole of an amide.
B. Hoffmann bromamide reaction is not given by alkyl amides.
C. Primary amines can be synthesized by Hoffmann bromamide degradation.
D. Secondary amide on reaction with $Br_2$ and NaOH will give secondary amine.
E. The by-products of Hoffmann degradation are $Na_2CO_3$, $NaBr$ and $H_2O$.

Updated On: Apr 12, 2026
  • A, C and E only
  • B, C and D only
  • C and E only
  • C, D and E only
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The Hoffmann Bromamide reaction converts a primary amide into a primary amine with one less carbon atom.
Step 2: Key Formula or Approach:
The balanced equation is: \[ R-CONH_2 + Br_2 + 4NaOH \rightarrow R-NH_2 + Na_2CO_3 + 2NaBr + 2H_2O \]
Step 3: Detailed Explanation:
A: Only 1 mole of $Br_2$ is consumed, not 2. (False)
B: It is given by both alkyl and aryl primary amides. (False)
C: It is a primary method for preparing primary amines ($R-NH_2$). (True)
D: Secondary amides ($R-CONHR'$) do not undergo this reaction. (False)
E: The by-products are exactly $Na_2CO_3$, $NaBr$, and $H_2O$. (True)
Step 4: Final Answer:
Statements C and E are true.
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