Question:
Which one of the following parameters changes upon doubling the enzyme concentration?
Which one of the following parameters changes upon doubling the enzyme concentration?
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The \( V_{max} \) of an enzyme-catalyzed reaction is directly proportional to the enzyme concentration. Increasing the enzyme concentration increases the maximum velocity of the reaction.
Updated On: Dec 11, 2025
- \( K_M \)
- \( V_{max} \)
- \( k_{cat} \)
- \( K_{eq} \)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding enzyme kinetics.
The Michaelis-Menten constant \( K_M \) and the catalytic rate constant \( k_{cat} \) are intrinsic properties of the enzyme and do not change with enzyme concentration. However, \( V_{max} \), which represents the maximum reaction velocity, is directly proportional to enzyme concentration.
Step 2: Analyzing the options.
(A) \( K_M \): Incorrect — \( K_M \) is independent of enzyme concentration.
(B) \( V_{max} \): Correct — \( V_{max} \) increases when enzyme concentration is doubled.
(C) \( k_{cat} \): Incorrect — \( k_{cat} \) is a constant that does not change with enzyme concentration.
(D) \( K_{eq} \): Incorrect — \( K_{eq} \) is related to the equilibrium constant and does not depend on enzyme concentration.
Step 3: Conclusion.
The correct answer is (B) \( V_{max} \), as doubling the enzyme concentration increases \( V_{max} \).
The Michaelis-Menten constant \( K_M \) and the catalytic rate constant \( k_{cat} \) are intrinsic properties of the enzyme and do not change with enzyme concentration. However, \( V_{max} \), which represents the maximum reaction velocity, is directly proportional to enzyme concentration.
Step 2: Analyzing the options.
(A) \( K_M \): Incorrect — \( K_M \) is independent of enzyme concentration.
(B) \( V_{max} \): Correct — \( V_{max} \) increases when enzyme concentration is doubled.
(C) \( k_{cat} \): Incorrect — \( k_{cat} \) is a constant that does not change with enzyme concentration.
(D) \( K_{eq} \): Incorrect — \( K_{eq} \) is related to the equilibrium constant and does not depend on enzyme concentration.
Step 3: Conclusion.
The correct answer is (B) \( V_{max} \), as doubling the enzyme concentration increases \( V_{max} \).
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