Question:

Which one of the following graphs is not correct for ideal gas?

d = Density, P = Pressure, T = Temperature

Show Hint

For an ideal gas \(d = \frac{PM}{RT}\). Check how d varies with T, 1/T and P.
Updated On: Nov 5, 2026
  • II
  • III
  • I
  • IV
Show Solution
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The Correct Option is A

Solution and Explanation

For an ideal gas, \(PV = nRT \Rightarrow d = \frac{PM}{RT}\).
Graph I: d vs T at constant P is a decreasing hyperbola (\(d \propto 1/T\)), correct.
Graph II: d vs T is drawn as a straight line with positive slope, but d decreases with T, so this is not correct.
Graph III: d vs 1/T is a straight line (\(d \propto 1/T\)), correct.
Graph IV: d vs P is a straight line (\(d \propto P\) at constant T), correct.
So the incorrect graph is II.
Answer: (1) II
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