Question:

Which one of the following carboxylic acids has the highest $\text{p}K_a$ value?}

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Stronger electron-donating alkyl groups increase $\text{p}K_a$ by destabilizing the carboxylate ion.
Updated On: Jun 12, 2026
  • Benzoic acid ($\text{C}_6\text{H}_5\text{COOH}$)
  • Phenylacetic acid ($\text{C}_6\text{H}_5\text{CH}_2\text{COOH}$)
  • Ethanoic acid ($\text{CH}_3\text{COOH}$)
  • Propanoic acid ($\text{CH}_3\text{CH}_2\text{COOH}$)
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The Correct Option is D

Solution and Explanation

Concept: $\text{p}K_a = -\log K_a$. A higher $\text{p}K_a$ means a weaker acid. Acid strength depends on stability of the conjugate base ($\text{RCOO}^-$). Electron-withdrawing groups stabilize the conjugate base and increase acidity, while electron-donating groups destabilize it and decrease acidity.

Step 1:
Benzoic acid.
The phenyl ring shows a mild $-I$ effect, stabilizing the carboxylate ion. Hence it is relatively more acidic.

Step 2:
Phenylacetic acid.
The phenyl group is separated by $-CH_2-$, reducing resonance but still showing $-I$ effect, making it moderately acidic.

Step 3:
Ethanoic acid.
The methyl group shows $+I$ effect, slightly decreasing acidity.

Step 4:
Propanoic acid.
The ethyl group shows stronger $+I$ effect than methyl group, further destabilizing the carboxylate ion, making it the weakest acid. Conclusion:
Propanoic acid is the weakest acid among the given options, hence it has the highest $\text{p}K_a$ value.
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