Among the given metals, sodium (Na) has the highest oxidation potential in the alkali metal group. The oxidation potential is a measure of an element's tendency to lose electrons and undergo oxidation. In alkali metals, the higher the oxidation potential, the weaker the reducing agent the metal is. Sodium, having the highest oxidation potential in this group, is therefore the weakest reducing agent. This is because a higher oxidation potential means that sodium is less inclined to lose electrons compared to other alkali metals.
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
