Question:

Which of the graphs shown below does not represent the relationship between incident light and the electron ejected from metal surface ?

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Einstein: K.E. = h\(\nu\) - h\(\nu_0\). Electrons are ejected only above the threshold frequency, so the K.E. line cannot start at the origin.
Updated On: Nov 5, 2026
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The Correct Option is B

Solution and Explanation

Photoelectric equation: \(\mathrm{K.E.} = h\nu - h\nu_0\).
Option (1): K.E. vs energy of light is zero up to the work function, then rises linearly: correct.
Option (2): K.E. vs frequency drawn as a straight line through the origin: incorrect, because no electron is emitted below the threshold frequency \(\nu_0\); the line must start at \(\nu_0\) on the frequency axis.
Option (3): K.E. vs intensity is constant (K.E. depends on frequency, not intensity): correct.
Option (4): number of electrons vs frequency is zero below \(\nu_0\) and constant (for fixed intensity) above it: acceptable.
Answer: (2) the graph of K.E. of electrons vs frequency starting from the origin
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