Complete hydrolysis of xenon hexafluoride is
\[
\boxed{
\mathrm{XeF_6+3H_2O\rightarrow XeO_3+6HF}
}
\]
The product is xenon trioxide, not elemental xenon.
The first ionization enthalpy of molecular oxygen is almost identical with that of xenon
Chlorine with excess ammonia gives nitrogen as one of the products
\(\mathrm{XeF_6}\) on complete hydrolysis gives Xe, HF and \(\mathrm{O_2}\)
The oxidizing agent used in Deacon's process is atmospheric oxygen
Show Solution
Verified By Collegedunia
The Correct Option isC
Solution and Explanation
Step 1: Examine each statement.
\[
\boxed{\text{(A) Correct}}
\]
The first ionization enthalpy of \(\mathrm{O_2}\) is nearly equal to that of Xe.
\[
\boxed{\text{(B) Correct}}
\]
With excess ammonia,
\[
3\mathrm{Cl_2}+8\mathrm{NH_3}
\rightarrow
6\mathrm{NH_4Cl}+\mathrm{N_2}
\]
Hence nitrogen is formed.
\[
\boxed{\text{(D) Correct}}
\]
In Deacon's process, atmospheric oxygen oxidizes HCl to chlorine.
Step 2: Check Statement (C).
Complete hydrolysis of
\[
\mathrm{XeF_6}
\]
produces
\[
\boxed{\mathrm{XeO_3}}
\]
and HF.
It does not produce Xe and \(\mathrm{O_2}\).
Hence Statement (C) is incorrect.
Therefore,
\[
\boxed{(C)}
\]
is the correct answer.