Step 1: Use Maxwell relations.
Thermodynamic identities:
$dF = -S\,dT - P\,dV$ (not +P dV) → (C) is false.
$dG = -S\,dT + V\,dP$ → (D) correct.
Step 2: Entropy differential identities.
Using exact relations for $S(T,V)$:
$TdS = C_V dT + T\left(\frac{\partial P}{\partial T}\right)_V dV$ → (A) correct.
$TdS = C_P dT - T\left(\frac{\partial V}{\partial T}\right)_P dP$ → (B) is incorrect sign.
Step 3: Conclusion.
Correct statements are (A) and (D).

At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/m³, which is dimensionally incorrect for a spectral density. The correct unit J/(m³·Hz) or J·s/m³ is used here for the solution.)

