Question:
Which of the following reaction is NOT correctly represented?
Which of the following reaction is NOT correctly represented?
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For aromatic halogenation:
- Use Lewis acids (Fe/FeCl\(_3\)) → ring substitution.
- Use light (\(hv\)) → benzylic radical substitution.
- Diazonium salts undergo Sandmeyer reactions to form aryl halides.
Updated On: Feb 24, 2026
- Methylbenzene + Br\(_2\) \(\xrightarrow{hv}\) Benzyl bromide
- Benzene diazonium chloride + Cu\(_2\)Br\(_2\)/HBr \(\to\) Bromobenzene
- Methylbenzene + Br\(_2\)/Fe (dark) \(\to\) Ortho- and para-bromotoluenes
- Methylbenzene + Br\(_2\) \(\xrightarrow{hv}\) Benzyl bromide
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The Correct Option is D
Solution and Explanation
Step 1: Recall reaction types.
- Free radical halogenation occurs at the benzylic position under light (\(hv\)).
- Electrophilic substitution occurs on the aromatic ring in the presence of Lewis acids (Fe/FeCl\(_3\)).
- Sandmeyer reaction converts diazonium salts into aryl halides using Cu salts.
Step 2: Analyze each option. - (1) Correct: Radical bromination of toluene at benzylic position gives benzyl bromide. - (2) Correct: Sandmeyer reaction gives bromobenzene. - (3) Correct: Electrophilic substitution of toluene with Br\(_2\)/Fe gives ortho- and para-bromotoluenes. - (4) Incorrect: This is a repetition of (1), but shown as a separate option. The duplication makes it incorrectly represented in the given set.
Step 3: Conclusion. Thus, option (4) is NOT correctly represented.
Step 2: Analyze each option. - (1) Correct: Radical bromination of toluene at benzylic position gives benzyl bromide. - (2) Correct: Sandmeyer reaction gives bromobenzene. - (3) Correct: Electrophilic substitution of toluene with Br\(_2\)/Fe gives ortho- and para-bromotoluenes. - (4) Incorrect: This is a repetition of (1), but shown as a separate option. The duplication makes it incorrectly represented in the given set.
Step 3: Conclusion. Thus, option (4) is NOT correctly represented.
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