To solve the problem of determining what substances are formed when potassium permanganate (\(KMnO_4\)) decomposes upon heating at 513 K, we need to understand the chemical decomposition reaction involved.
When \(KMnO_4\) is heated, it decomposes into potassium manganate (\(K_2MnO_4\)), manganese dioxide (\(MnO_2\)), and oxygen gas (\(O_2\)). The balanced chemical reaction for this decomposition is given by:
| \(2KMnO_4 \rightarrow K_2MnO_4 + MnO_2 + O_2\) |
Let's analyze the options:
The only option that correctly represents the components formed by the decomposition of \(KMnO_4\) is:
Thus, the correct answer is:
\(KMnO_4\) decomposes upon heating at 513 K and forms \(K_2MnO_4\) and \(MnO_2\).
\(2KMnO4 \xrightarrow{\Delta} K_2MnO_4 + O2 + MnO2\)
So, the Correct option is (B): \(K_2MnO_4\), \(MnO_2\)

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.