To solve the problem of determining what substances are formed when potassium permanganate (\(KMnO_4\)) decomposes upon heating at 513 K, we need to understand the chemical decomposition reaction involved.
When \(KMnO_4\) is heated, it decomposes into potassium manganate (\(K_2MnO_4\)), manganese dioxide (\(MnO_2\)), and oxygen gas (\(O_2\)). The balanced chemical reaction for this decomposition is given by:
| \(2KMnO_4 \rightarrow K_2MnO_4 + MnO_2 + O_2\) |
Let's analyze the options:
The only option that correctly represents the components formed by the decomposition of \(KMnO_4\) is:
Thus, the correct answer is:
\(KMnO_4\) decomposes upon heating at 513 K and forms \(K_2MnO_4\) and \(MnO_2\).
\(2KMnO4 \xrightarrow{\Delta} K_2MnO_4 + O2 + MnO2\)
So, the Correct option is (B): \(K_2MnO_4\), \(MnO_2\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
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There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.