Question

Match List I with List II:

• A. A – II, B – I, C – IV, D – III
• B. A – I, B – III, C – II, D – I
• C. A – I, B – II, C – IV, D – III
• D. A – IV, B – I, C – III, D – II

Hint:

In organic chemistry, different reactions are often classified based on the type of halogen substitution or exchange that occurs. Recognizing these patterns will help identify the correct type of reaction.

Answer 1

The Correct Option is A

To match the reactions from List I with their corresponding names in List II, let's analyze each case:

(A) The compound in List I is \(\text{C}_6\text{H}_4\text{Cl}\text{CH}_3\text{Cl}.\) This is a case of the Wurtz reaction, which involves halogenated alkyl compounds reacting with sodium metal to form alkyl chains. This matches the reaction in List II as:
Correct Match: A – II Wurtz Fitting reaction.

(B) The compound in List I is a chlorobenzene \(\text{C}_6\text{H}_5\text{Cl}\). The reaction here involves chlorobenzene and sodium metal, which is characteristic of the Fitting reaction, where aromatic halides are involved. Hence, the correct match is:
Correct Match: B – I Fitting reaction.

(C) The compound in List I is \(\text{C}_6\text{H}_4\text{Cl}\) with a nitro group \(\text{C}_6\text{H}_4\text{NO}_2\text{Cl}\). This type of reaction is the Sandmeyer reaction, which is used to replace halides (like chlorine) with other groups, especially when the aromatic compound has a nitro group, as in this case. Therefore, the correct match is:
Correct Match: C – IV Sandmeyer reaction

(D) The compound in List I is \(\text{C}_2\text{H}_5\text{Cl}\) with sodium iodide. This is a typical example of a Finkelstein reaction, which involves the exchange of halides. In this case, chlorine is replaced by iodine in the presence of sodium iodide. Thus, the correct match is:
Correct Match: D – III Finkelstein reaction.

So, the correct option is (A): A – II, B – I, C – IV, D – III