Question:
Which of the following molecules is eliminated during peptide bond formation?
Which of the following molecules is eliminated during peptide bond formation?
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Peptide bond formation is a condensation reaction because a water molecule is eliminated during bond formation.
Updated On: Jun 15, 2026
- \(\mathrm{H_2O}\)
- \(\mathrm{NH_3}\)
- \(\mathrm{CH_3OH}\)
- \(\mathrm{CO_2}\)
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The Correct Option is A
Solution and Explanation
Step 1: Understand peptide bond formation.
A peptide bond is formed between two amino acids.
The carboxyl group \((-\mathrm{COOH})\) of one amino acid reacts with the amino group \((-\mathrm{NH_2})\) of another amino acid.
Step 2: Identify the eliminated groups.
During this reaction:
\[ -\mathrm{OH} \] comes from the carboxyl group and
\[ -\mathrm{H} \] comes from the amino group.
These combine together to form water.
Step 3: Write the reaction.
\[ \mathrm{R-COOH+H_2N-R'\rightarrow R-CONH-R'+H_2O} \]
The linkage \((-\mathrm{CONH}-)\) formed is called the peptide bond.
Step 4: Eliminate incorrect options.
\(\mathrm{NH_3}\), \(\mathrm{CH_3OH}\), and \(\mathrm{CO_2}\) are not released during peptide bond formation.
Step 5: Final conclusion.
Hence, the molecule eliminated during peptide bond formation is
\[ \boxed{\mathrm{H_2O}} \]
A peptide bond is formed between two amino acids.
The carboxyl group \((-\mathrm{COOH})\) of one amino acid reacts with the amino group \((-\mathrm{NH_2})\) of another amino acid.
Step 2: Identify the eliminated groups.
During this reaction:
\[ -\mathrm{OH} \] comes from the carboxyl group and
\[ -\mathrm{H} \] comes from the amino group.
These combine together to form water.
Step 3: Write the reaction.
\[ \mathrm{R-COOH+H_2N-R'\rightarrow R-CONH-R'+H_2O} \]
The linkage \((-\mathrm{CONH}-)\) formed is called the peptide bond.
Step 4: Eliminate incorrect options.
\(\mathrm{NH_3}\), \(\mathrm{CH_3OH}\), and \(\mathrm{CO_2}\) are not released during peptide bond formation.
Step 5: Final conclusion.
Hence, the molecule eliminated during peptide bond formation is
\[ \boxed{\mathrm{H_2O}} \]
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