Question:

Which of the following is paramagnetic ?

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Fill the molecular orbital diagram and look for unpaired electrons; \(\mathrm{B_2}\) has two unpaired electrons in degenerate \(\pi\) orbitals.
Updated On: Nov 11, 2026
  • \(\mathrm{NO^+}\)
  • CO
  • \(\mathrm{O_2^{2-}}\)
  • \(\mathrm{B_2}\)
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The Correct Option is D

Solution and Explanation

\(\mathrm{NO^+}\) has 14 electrons (isoelectronic with \(\mathrm{N_2}\) and CO): all paired, diamagnetic.
CO has 14 electrons, \(\sigma_{2s}^2 \sigma_{2s}^{*2} \pi_{2p}^4 \sigma_{2p}^2\): diamagnetic.
\(\mathrm{O_2^{2-}}\) has 18 electrons (like \(\mathrm{F_2}\)): \(\pi^{*}\) orbitals completely filled, diamagnetic.
\(\mathrm{B_2}\) has 10 electrons: \(\sigma_{2s}^2 \sigma_{2s}^{*2} \pi_{2p_x}^1 \pi_{2p_y}^1\), two unpaired electrons, paramagnetic.
Answer: (4) \(\mathrm{B_2}\)
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