Question:
Which of the following is formed when acetamide reacts with Br$_2$/KOH?
Which of the following is formed when acetamide reacts with Br$_2$/KOH?
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Hofmann bromamide reaction converts amides into primary amines with one carbon less.
Updated On: Oct 14, 2025
- Acetone
- Methyl amine
- Acetaldehyde
- Ammonia
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The Correct Option is B
Solution and Explanation
Step 1: Recall the reaction.
Acetamide reacts with Br$_2$/KOH in the Hofmann bromamide reaction.
Step 2: Reaction details.
R–CONH$_2$ \(\xrightarrow{Br_2/KOH}\) R–NH$_2$ + CO$_2$.
Here, CH$_3$CONH$_2$ → CH$_3$NH$_2$.
Step 3: Conclusion.
The product is methyl amine.
Acetamide reacts with Br$_2$/KOH in the Hofmann bromamide reaction.
Step 2: Reaction details.
R–CONH$_2$ \(\xrightarrow{Br_2/KOH}\) R–NH$_2$ + CO$_2$.
Here, CH$_3$CONH$_2$ → CH$_3$NH$_2$.
Step 3: Conclusion.
The product is methyl amine.
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