Question:

Which of the following graphs correctly represents the variation of thermodynamic properties of Haber's process?

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Haber process is exothermic with negative entropy change; use $-\Delta G/T = -\Delta H/T + \Delta S$.
Updated On: Oct 26, 2026
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The Correct Option is A

Solution and Explanation

The Haber process $N_2 + 3H_2 \rightleftharpoons 2NH_3$ is exothermic ($\Delta H^\theta < 0$) and has a negative entropy change ($\Delta S^\theta < 0$); both vary only slightly with temperature.
$-\Delta H^\theta/T$ is therefore positive and falls towards zero as $T$ increases, and $-\Delta G^\theta/T = -\Delta H^\theta/T + \Delta S^\theta$ starts positive, falls below $-\Delta H^\theta/T$ and crosses zero (at the temperature where $\Delta G^\theta = 0$), becoming negative.
Only graph (1) shows these trends together with a negative, nearly constant $\Delta H^\theta$ and $\Delta S^\theta$: option (1).
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