Step 1: Recall oxidation rules.
Secondary alcohols oxidize to ketones. Primary alcohols/aldehydes oxidize to acids.
Step 2: Classify options.
(A) Acetaldehyde (aldehyde) \(\rightarrow\) acetic acid.
(B) Ethanol (primary alcohol) \(\rightarrow\) acetaldehyde/acetic acid.
(C) Isopropyl alcohol (secondary) \(\rightarrow\) acetone.
(D) Methanol (primary) \(\rightarrow\) formaldehyde/formic acid.
Step 3: Conclusion.
Therefore, CH$_3$CHOHCH$_3$ gives acetone on oxidation.