Question:
Which of the following does not exist?
Which of the following does not exist?
Show Hint
For lead:
\[
Pb^{2+}
\]
is more stable than
\[
Pb^{4+}
\]
because of the inert pair effect.
Updated On: Jun 17, 2026
- $SnF_4$
- $PbF_4$
- $PbI_4$
- $CF_4$
Show Solution
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The Correct Option is C
Solution and Explanation
Concept:
The inert pair effect becomes increasingly important down Group 14.
Lead prefers the +2 oxidation state over +4.
Step 1: Examine the compounds.
\[ SnF_4 \] exists and is stable. \[ PbF_4 \] also exists because fluorine stabilizes the +4 oxidation state. \[ CF_4 \] is a well-known stable compound.
Step 2: Consider lead tetraiodide.
\[ PbI_4 \] is unstable because iodide ion readily reduces \[ Pb^{4+} \] to \[ Pb^{2+} \] Therefore it does not exist as a stable compound. \[ PbI_4 \rightarrow PbI_2 + I_2 \]
Step 3: State the answer.
\[ \boxed{PbI_4} \]
Step 1: Examine the compounds.
\[ SnF_4 \] exists and is stable. \[ PbF_4 \] also exists because fluorine stabilizes the +4 oxidation state. \[ CF_4 \] is a well-known stable compound.
Step 2: Consider lead tetraiodide.
\[ PbI_4 \] is unstable because iodide ion readily reduces \[ Pb^{4+} \] to \[ Pb^{2+} \] Therefore it does not exist as a stable compound. \[ PbI_4 \rightarrow PbI_2 + I_2 \]
Step 3: State the answer.
\[ \boxed{PbI_4} \]
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