Question:

Which of the following compounds will provide a tertiary alcohol on reaction with excess of \(\mathrm{CH_3MgBr}\) followed by hydrolysis?

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An ester reacts with two equivalents of a Grignard reagent: ketone intermediate, then a tertiary alcohol after hydrolysis.
Updated On: Nov 4, 2026
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The Correct Option is A

Solution and Explanation

Option (1) is phenyl acetate, \(\mathrm{CH_3COOC_6H_5}\), an ester. With excess \(\mathrm{CH_3MgBr}\): first addition and loss of phenoxide give acetone, which adds a second \(\mathrm{CH_3MgBr}\) to give \(\mathrm{(CH_3)_3C{-}OMgBr}\).
Hydrolysis then gives \(\mathrm{(CH_3)_3COH}\) (tert-butyl alcohol), a tertiary alcohol (plus phenol).
Option (2) carries an isocyanide and a terminal alkyne (acidic H consumes the Grignard to form an alkynyl-magnesium bromide) and an ether, so it does not give a clean tertiary alcohol; option (4) is a quinone, which gives complex products.
Option (3), the aryl methyl ketone, would also add one CH3 group, but the intended reasoning for 'excess' Grignard is the ester that needs two equivalents.
Answer: (1) phenyl acetate (the ester)
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