Which of the following compounds shows geometrical isomerism?
Show Hint
- 2-methylpent-1-ene
- 4-methylpent-1-ene
- 2-methylpent-2-ene
- 4-methylpent-2-ene
The Correct Option is D
Solution and Explanation
(1) 2-methylpent-1-ene: CH2=C(CH3)CH2CH2CH3. C-1 carries two H atoms, so no cis-trans isomerism.
(2) 4-methylpent-1-ene: CH2=CH-CH2-CH(CH3)2. C-1 carries two H atoms, so no.
(3) 2-methylpent-2-ene: (CH3)2C=CH-CH2CH3. C-2 carries two identical CH3 groups, so no.
(4) 4-methylpent-2-ene: CH3-CH=CH-CH(CH3)2. C-2 carries H and CH3; C-3 carries H and isopropyl. Both carbons have two different groups, so cis and trans forms exist.
Answer: (4) 4-methylpent-2-ene
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