Question:

Which of the following compounds does not exhibit resonance?

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Resonance needs a lone pair or pi bond on an atom directly attached to a pi bond or ring; in option (4) the NH2 is separated from the C=C by a CH2.
Updated On: Nov 4, 2026
  • \(\mathrm{CH_3CH_2OCH=CH_2}\)
  • \(\mathrm{CH_3CH_2CH_2CONH_2}\)
  • \(\mathrm{CH_3CH_2CH=CHCH_2NH_2}\)
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The Correct Option is D

Solution and Explanation

(1) \(\mathrm{CH_3CH_2\ddot{O}CH=CH_2}\): the oxygen lone pair is conjugated with the C=C (vinyl ether), so resonance is possible.
(2) Benzyl alcohol: the benzene ring itself shows resonance.
(3) \(\mathrm{CH_3CH_2CH_2CONH_2}\): the nitrogen lone pair is conjugated with C=O (amide resonance).
(4) \(\mathrm{CH_3CH_2CH=CHCH_2NH_2}\): the \(\mathrm{NH_2}\) is attached to an sp3 carbon (\(\mathrm{CH_2}\)) that separates it from the C=C, so the lone pair is not conjugated; there is no resonance.
Answer: (4) \(\mathrm{CH_3CH_2CH=CHCH_2NH_2}\)
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