Question:

Which of the following complexes will shows geometrical isomerism ?

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An octahedral complex of type \(\mathrm{[M(AA)_2bc]}\) exists as cis and trans forms; \(\mathrm{[Ma_5b]}\), \(\mathrm{[M(AA)_3]}\) and square planar \(\mathrm{[MAB_3]}\) do not show geometrical isomerism.
Updated On: Nov 11, 2026
  • aquachlorobis (ethylenediamine) cobalt (II) chloride
  • pentaaquachlorohromium (III) chloride
  • potassium amminetrichloropltinate (II)
  • potassium tris(oxalato) chromate (III)
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The Correct Option is A

Solution and Explanation

(1) Aquachlorobis(ethylenediamine)cobalt chloride: octahedral of type \(\mathrm{[M(AA)_2bc]}\) with two en rings plus \(\mathrm{H_2O}\) and \(\mathrm{Cl}\); the two monodentate ligands can be cis or trans, so it shows geometrical isomerism.
(2) Pentaaquachlorochromium(III) chloride: type \(\mathrm{[Ma_5b]}\), only one arrangement.
(3) Potassium amminetrichloroplatinate(II): square planar \(\mathrm{[MAB_3]}\), only one arrangement.
(4) Potassium tris(oxalato)chromate(III): type \(\mathrm{[M(AA)_3]}\), shows only optical isomerism.
Answer: (1) aquachlorobis (ethylenediamine) cobalt (II) chloride
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