(i) \(\frac{2}{3}\), \(\frac{5}{2}\)
By converting these into like fractions,
\(\frac{2}{3}\) = \(\frac{2\times 2}{3\times 2}\)= 4/6
\(\frac{5}{2}\)= \(\frac{5\times 3}{2\times 3}\) =\(\frac{15}{6}\)
As 15 > 4, therefore, \(\frac{5}{2}\) is greater.
(ii) -\(\frac{5}{6}\), -\(\frac{4}{3}\)
-\(\frac{4}{3}\) = -\(\frac{4\times 2}{3\times 2}\) = -\(\frac{8}{6}\)
As -5>-8, therefore, -\(\frac{5}{6}\) is greater.


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |



| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
