Question

Which among the following compounds give yellow solid when reacted with NaOI/NaOH?
Choose the correct answer from the options given below:

• A. (B), (C) and (E) Only
• B. (A) and (C) Only
• C. (C) and (D) Only
• D. (A), (C) and (D) Only

Hint:

The reaction of alcohols with NaOI/NaOH often leads to yellow solid formation due to iodine complexation.

Answer 1

The Correct Option is B

The given question asks which compounds produce a yellow solid when reacted with NaOI/NaOH. This reaction is characteristic of the Haloform reaction, which occurs with methyl ketones (compounds containing the structure CH₃COR) and gives a yellow precipitate of iodoform (CHI₃).

1. Identify the Compounds:
   • (A) CH₃-CH(OH)-C₂H₅
   • (B) CH₃-CH₂-CH₂-OH
   • (C) CH₃COC₂H₅
   • (D) CH₃COOH
   • (E) CH₃CH₂CHO
2. Determine Which Compounds are Methyl Ketones:
   • Compound (C): CH₃COC₂H₅ is a methyl ketone and will react to form iodoform.
   • Compound (A): Upon oxidation with NaOI, CH₃-CH(OH)-C₂H₅ can yield a methyl ketone structure (acetone), thus forming iodoform.
   • Other Compounds: Compounds (B), (D), and (E) do not have the methyl ketone structure necessary for the iodoform reaction under standard conditions. Compound (E) is an aldehyde and will not react to form iodoform.
3. Conclusion: Based on the above analysis, the compounds (A) and (C) give a yellow solid (iodoform) when reacted with NaOI/NaOH.

The correct answer is (A) and (C) Only.

Answer 2

When alcohols are reacted with NaOI/NaOH, a yellow solid is produced due to the formation of iodine complexes. 
Upon examining the compounds: 
- (A) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_5 \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid. 
- (B) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_2 \text{OH} \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid. 
- (C) \( \text{CH}_3 \text{C}_2 \text{H}_5 \) (an aldehyde) does not react with NaOI/NaOH to produce a yellow solid. 
- (D) \( \text{CH}_3 \text{OH} \) does not react with NaOI/NaOH to form a yellow solid. 
- (E) \( \text{CH}_3 \text{CH}_2 \text{H} \) does not react with NaOI/NaOH to form a yellow solid. 
Thus, the correct answer is (2).