Work done in stretching the wire through $0.61 \,mm$ under the load of $3\, kg \,wt$.
$W_{1}$ $=\frac{1}{2}$ stretching force $\times$extension
$=\frac{1}{2}\times3\times9.8\times0.61\times10^{-3}$ $=8.967\times10^{-3} J$
Work done in stretching the wire through $1.02 \,mm$ under the load of $5 \,kg\, wt$.
$W_{2}$ $=\frac{1}{2}\times5\times9.8\times1.02\times10^{-3}$ $=24.99\times10^{-3}J$.
Hence the work done in stretching the wire from $0.61 \,mm$ to $1.02 \,mm$.
$\Delta W$ $=W_{2}-W_{1}$ $=\left(24.99-8.967\right)\times10^{-3}$ $\simeq$ $16\times10^{-3}J$