When \(\mathrm{XO_2}\) is fused with an alkali metal hydroxide in presence of an oxidizing agent such as \(\mathrm{KNO_3}\); a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. X is :
Show Hint
- Ti
- V
- Cr
- Mn
The Correct Option is D
Solution and Explanation
In acidic solution: \(\mathrm{3MnO_4^{2-} + 4H^+ \rightarrow 2MnO_4^- + MnO_2 + 2H_2O}\), giving the dark purple permanganate ion.
So X = Mn.
Answer: (4) Mn
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