Step 1: In the CE configuration, the output is 180\(^\circ\) out of phase with the input, which is a characteristic feature of the common emitter configuration.
Step 2: In both CB and CC configurations, the phase shift is either zero or a fraction of a degree, not 180\(^\circ\). Hence, the only correct answer is the CE configuration. Thus, the correct answer is option (2), CE - configuration.
In the given circuit, the electric currents through $15\, \Omega$ and $6 \, \Omega$ respectively are

In the given digital circuit, if the inputs are \( A = 1, B = 1 \) and \( C = 1 \), then the values of \( y_1 \) and \( y_2 \) are respectively

The voltage \( V_o \) in the network shown is
