Question

When a = 0, b = – 1, find the value of the given expressions: (i) 2a+2b (ii) 2a²+b²+1 (iii) 2a²b+2ab²+ab (iv) a²+ab+2

Answer 1

(i) 2a+2b = 2(0)+2(-1) = 0-2=-2 [putting a=0,b=-1]

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(ii) 2a²+b²+1 = 2(0)²+(-1)²+1 = 2×0+1+1 = 0+2 = 2 [putting a=0,b=-1]

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(iii) 2a²b+2ab²+ab = 2(0)²(-1)+2(0)(-1)²+(0)(-1) = 0+0+0 = 0 [putting a=0,b=-1]

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(iv) a2+ab+2 = (0)²+(0)(-1)+2 = 2 [putting a = 0,b=-1]