The given expression is \( \sin \theta \times \cot \theta \).
First, recall the identity for cotangent:
\[
\cot \theta = \frac{\cos \theta}{\sin \theta}.
\]
So:
\[
\sin \theta \times \cot \theta = \sin \theta \times \frac{\cos \theta}{\sin \theta} = \cos \theta.
\]
The reciprocal of \( \cos \theta \) is \( \sec \theta \), which is the correct answer.
Thus, the reciprocal is \( \boxed{\csc \theta} \).