Question:
What is the product Y in the given reaction sequence?
\[
CH_3COOH
\xrightarrow{\text{(i) } NH_3 \text{ (ii) } \Delta}
X
\xrightarrow{Br_2/NaOH}
Y
\]
What is the product Y in the given reaction sequence?
\[
CH_3COOH
\xrightarrow{\text{(i) } NH_3 \text{ (ii) } \Delta}
X
\xrightarrow{Br_2/NaOH}
Y
\]
Show Hint
Hofmann bromamide degradation converts an amide into a primary amine containing one less carbon atom than the original amide.
Updated On: Jun 18, 2026
- \(CH_3CH_2Br\)
- \(CH_3COONa\)
- \(CH_3NH_2\)
- \((CH_3)_2NH\)
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Concept:
Carboxylic acids react with ammonia to form ammonium salts, which on heating form amides. Amides undergo Hofmann bromamide degradation to give amines containing one carbon atom less.
Step 1: Formation of acetamide.
\[ CH_3COOH + NH_3 \rightarrow CH_3COONH_4 \] Ammonium acetate is formed. On heating, \[ CH_3COONH_4 \rightarrow CH_3CONH_2 + H_2O \] Thus \[ X=CH_3CONH_2 \] (acetamide)
Step 2: Apply Hofmann bromamide reaction.
\[ CH_3CONH_2 \xrightarrow{Br_2/NaOH} CH_3NH_2 \] The carbonyl carbon is removed as \(CO_2\).
Step 3: Identify the final product.
The product obtained is \[ CH_3NH_2 \] which is methylamine. \[ \boxed{Y=CH_3NH_2} \]
Step 1: Formation of acetamide.
\[ CH_3COOH + NH_3 \rightarrow CH_3COONH_4 \] Ammonium acetate is formed. On heating, \[ CH_3COONH_4 \rightarrow CH_3CONH_2 + H_2O \] Thus \[ X=CH_3CONH_2 \] (acetamide)
Step 2: Apply Hofmann bromamide reaction.
\[ CH_3CONH_2 \xrightarrow{Br_2/NaOH} CH_3NH_2 \] The carbonyl carbon is removed as \(CO_2\).
Step 3: Identify the final product.
The product obtained is \[ CH_3NH_2 \] which is methylamine. \[ \boxed{Y=CH_3NH_2} \]
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